Y=-0.01x^2+.7x+5.9

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Solution for Y=-0.01x^2+.7x+5.9 equation:



=-0.01Y^2+.7Y+5.9
We move all terms to the left:
-(-0.01Y^2+.7Y+5.9)=0
We get rid of parentheses
0.01Y^2-.7Y-5.9=0
We add all the numbers together, and all the variables
0.01Y^2-0.7Y-5.9=0
a = 0.01; b = -0.7; c = -5.9;
Δ = b2-4ac
Δ = -0.72-4·0.01·(-5.9)
Δ = 0.726
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.7)-\sqrt{0.726}}{2*0.01}=\frac{0.7-\sqrt{0.726}}{0.02} $
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.7)+\sqrt{0.726}}{2*0.01}=\frac{0.7+\sqrt{0.726}}{0.02} $

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